java按钮竖行排列

Java Swing（初学者）：有6个文本框竖直排列和两个按钮(bt1和bt2)，默认焦点在第一个文本框上。

以前写的，功能差不多，用1，2，3，4。。代替了。自己看一下吧

ctrl+1  表示选择编号为1的按钮。上下键控制位置变化

package eventDemo;

import java.awt.FlowLayout;

import java.awt.KeyEventPostProcessor;

import java.awt.KeyboardFocusManager;

import java.awt.event.InputEvent;

import java.awt.event.KeyEvent;

import java.awt.event.KeyListener;

import javax.swing.JButton;

import javax.swing.JFrame;

public class KeyEventDemo implements KeyListener{

JButton []b = new JButton[10];

int x,y;

JFrame jf;

KeyboardFocusManager manager;

public static void main(String []args){

new KeyEventDemo();

}

KeyEventDemo(){

manager = KeyboardFocusManager.getCurrentKeyboardFocusManager();//看这里。。。。。。。。。。。。。。。改成setCurrentKeyboardFocusManager()，其他在改一下就可以了

manager.addKeyEventPostProcessor(new KeyEventPostProcessor() {

@Override

public boolean postProcessKeyEvent(KeyEvent e) {

// TODO Auto-generated method stub

if ((e.getModifiersEx()  InputEvent.CTRL_DOWN_MASK) !=0){

if (e.getKeyCode()==KeyEvent.VK_1){

//System.out.println(“11”);

b[1].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_2){

System.out.println(“11”);

b[2].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_3){

System.out.println(“11”);

b[3].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_4){

System.out.println(“11”);

b[4].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_5){

System.out.println(“11”);

b[5].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_6){

System.out.println(“11”);

b[6].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_7){

System.out.println(“11”);

b[7].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_8){

System.out.println(“11”);

b[8].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_9){

System.out.println(“11”);

b[9].requestFocus();

}

if (e.getKeyCode()==KeyEvent.VK_0){

System.out.println(“11”);

b[0].requestFocus();

}

}

return false;

}

});

jf = new JFrame(“KeyEventDemo”);

jf.setLayout(new FlowLayout());

for (int i = 0; i =9; i++) {

b[i] = new JButton(i+””);

jf.add(b[i]);

b[i].addKeyListener(this);

}

jf.setBounds(600,200,200,200);

jf.setVisible(true);

jf.validate();

jf.addKeyListener(new KeyListener() {

@Override

public void keyTyped(KeyEvent e) {

// TODO Auto-generated method stub

if (e.getKeyCode() == KeyEvent.VK_0)

System.out.println(‘0’);

}

@Override

public void keyReleased(KeyEvent e) {

// TODO Auto-generated method stub

}

@Override

public void keyPressed(KeyEvent e) {

// TODO Auto-generated method stub

}

});

}

@Override

public void keyTyped(KeyEvent e) {

// TODO Auto-generated method stub

}

@Override

public void keyPressed(KeyEvent e) {

// TODO Auto-generated method stub

}

@Override

public void keyReleased(KeyEvent e) {

// TODO Auto-generated method stub

JButton temp = (JButton) e.getSource();

x = temp.getBounds().x;

y = temp.getBounds().y;

//System.out.println(x*y);

if (e.getKeyCode() == KeyEvent.VK_UP)

y = y – 20;

if (e.getKeyCode() == KeyEvent.VK_DOWN)

y = y + 20;

if (e.getKeyCode() == KeyEvent.VK_RIGHT)

x = x + 20;

if (e.getKeyCode() == KeyEvent.VK_LEFT)

x = x – 20;

temp.setLocation(x, y);

}

}

以下java程序，如何实现按钮垂直排序，且按钮大小不变。其他的实现不变。

进行容器的嵌套就能解决：

import javax.swing.*;

import java.awt.*;

public class Dashboard{

private static final long serialVersionUID = 1L;

JMenu m,m1;

JMenuBar mb;

public Dashboard(){

JFrame jf = new JFrame(“Dashboard”);

jf.setSize(700,300);

jf.setLocationRelativeTo(null);//窗口居中

jf.setBackground(Color.white);

m = new JMenu(“File”);

m1 = new JMenu(“Help”);

mb = new JMenuBar();

mb.add(m);

mb.add(m1);

JPanel Panel1 = new JPanel();

Panel1.setLayout(new GridLayout(5,3));

JLabel l1=new JLabel(“”);

JLabel l2=new JLabel(“”);

JLabel l3=new JLabel(“”);

JLabel l4=new JLabel(“”);

JLabel l5=new JLabel(“”);

JLabel l6=new JLabel(“”);

JLabel l7=new JLabel(“”);

JLabel l8=new JLabel(“”);

JLabel l9=new JLabel(“”);

JLabel l10=new JLabel(“”);

JLabel l11=new JLabel(“”);

JLabel l12=new JLabel(“”);

JLabel l13=new JLabel(“”);

JPanel Panel_left = new JPanel();

Panel_left.setBackground(Color.white);

Panel_left.setBorder(BorderFactory.createMatteBorder(5,5,5,10,Color.lightGray));

JPanel Panel_right = new JPanel();

Panel_right.setBackground(Color.white);

Panel_right.setBorder(BorderFactory.createMatteBorder(5,5,5,5,Color.lightGray));

JButton b_movementforecast = new JButton(“Movement Forecast”);

b_movementforecast.setPreferredSize(new Dimension(150, 40));

JButton b_yarddensity = new JButton(“Yard Density”);

b_yarddensity.setLocation(6, 60);

b_yarddensity.setPreferredSize(new Dimension(150, 40));

Panel1.add(l1);

Panel1.add(l2);

Panel1.add(l3);

Panel1.add(l4);

Panel1.add(b_movementforecast);

Panel1.add(l5);

Panel1.add(l6);

Panel1.add(l7);

Panel1.add(l8);

Panel1.add(l9);

Panel1.add(b_yarddensity);

Panel1.add(l10);

Panel1.add(l11);

Panel1.add(l12);

Panel1.add(l13);

Panel_left.add(Panel1);

jf.setJMenuBar(mb);

jf.getContentPane().add(Panel_left,”West”) ;

jf.add(Panel_right);

jf.setVisible(true);

jf.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

}

public static void main(String[] args){

new Dashboard();

}

}

java如何把GUI界面的按钮竖直排列

Class GridLayout

位于java.awt包下

构造方法之一

GridLayout(int rows, int cols)

一个参数传列数，第二个传行数

竖直排一列列数传1进去就可以了吧